Getting the file path from the FileUploader Control

Hi Experts,

I am using a FileUploader control in SAPUI5 to upload a file. I am able to get the Name of the file that I upload using the method getValue() of the sap.ui.commons.FileUploader, but what I need is the full path of this file.

For example

I select the file from a source

I am able to get the filename using the code

alert(oSimpleFileUploader.getValue());

but what I actually need is the location of this file

"C:\Users\Public\Videos\Sample Videos\Wildlife.wmv"

Is there a way to achieve this? Please help

Thanks and Regards,

Shreepad Patil